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AngelicSongx
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Sat Nov 03, 2012 6:15 pm 
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I was wondering if that would pop into this thread. But yep that's me too.

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Nachalnik
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Sun Nov 04, 2012 9:35 am 
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MrPotatoMan
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Sun Nov 04, 2012 6:57 pm 
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Potato
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Sun Nov 04, 2012 11:07 pm 
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musicandilikeit
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 12:24 pm 
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D-vid
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 12:31 pm 
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x = 1/9 * 4th root of 3

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Omnithea
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 12:41 pm 
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NEEEEEEEEEEEEEEEEEEEEEEERRRRRRRRRRRRRRRRRRRRRRRRRRRDDDDDDDDDDDDDDD!!!!!!!!!!!!!

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Stranaton
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 12:48 pm 
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Omnithea wrote:
NEEEEEEEEEEEEEEEEEEEEEEERRRRRRRRRRRRRRRRRRRRRRRRRRRDDDDDDDDDDDDDDD!!!!!!!!!!!!!

no, he's German :awesomeface:

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ZenithOfChaos
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 12:56 pm 
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Actually, x can be both positive and negative, since the absolute value is apparent in squares.

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Sollix
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 12:59 pm 
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Omnithea wrote:
NEEEEEEEEEEEEEEEEEEEEEEERRRRRRRRRRRRRRRRRRRRRRRRRRRDDDDDDDDDDDDDDD!!!!!!!!!!!!!


:V zen you walked right into that one

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ZenithOfChaos
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 1:00 pm 
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I'm not wearing my glasses. I can't see a thing without my glasses.

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Lolita wrote:
yesssss my transformation into a slut is complete

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D-vid
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 1:02 pm 
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x = (3x)² / 4th root of 3 // expand (3x)²
x = 9 x² / 4th root of 3 // * 4th root of 3
4th root of 3 * x = 9 x²
// now were x negative, then you'd have a negative value on the left and a positive on the right, so the negative x is false. /x

4th root of 3 = 9 x // * 1/9

4th root of 3 * 1/9 = x

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ZenithOfChaos
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 1:05 pm 
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HAHAHA! I knew I was wrong from the very beginning. You've fallen into my trap D-vid. Now, I can call you a DOUBLE NERD. Seriously, I knew I was wrong... I just wanted to see someone call me on it. Not sure why. I may be drunk.

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Lolita wrote:
yesssss my transformation into a slut is complete

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Sollix
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 1:07 pm 
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D-vid wrote:
x = (3x)² / 4th root of 3 // expand (3x)²
x = 9 x² / 4th root of 3 // * 4th root of 3
4th root of 3 * x = 9 x²
// now were x negative, then you'd have a negative value on the left and a positive on the right, so the negative x is false. /x

4th root of 3 = 9 x // * 1/9

4th root of 3 * 1/9 = x



Staaahhhhhp. My brains gonna explode

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ZenithOfChaos
 Post subject: Re: Gratuitous pictures of yourself 2
PostPosted: Mon Nov 05, 2012 1:09 pm 
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It's really not a complicated problem. The 4th root of three just looks really intimidating.

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Lolita wrote:
yesssss my transformation into a slut is complete

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