Quoted from Unimportant Topics
Flicky wrote:
>NJ ASK testing
>How do you turn a rectangle with the dimensions of 15 x 22 inches into a cylinder, and what would the volume of said cylinder be?
>What would the dimensions of the rectangle have to be to double the volume?

I HATE FINAL EXAMS
WHY ARE WE EVEN HAVING FINAL EXAMS IT'S APRIL SCHOOL DOESN'T END UNTIL JUNE
AAAAAAAAAAAAAAAAA
LETS DO MATHZ WITH MSPAINT
By Sol Reaper

We start off with our rectangle. Simple enough.

Now we wrap it around to create a cylinder with a height of 15 (the same height as the rectangle) and a circumference of 22 (the length of the cylinder)
The equation for Circumference is "C = 2(pi)radius". Using reverse solving we can figure out what the radius is. I'm going to use 3.14 for pi as I've been taught.
"22in = 2(3.14)r" is our new equation, after putting everything into place. The image above shows the rest of the steps.
Since the variable we need to find is "r", we need to isolate it. Since 6.28 is attached to r (married, if you will; r is trying to become single), we must divide 6.28 from both sides (divorcing) as required to keep the equation balanced. We end up with "r = 3.50" as 22/6.28 is 3.50.

Now that we have our radius it's just a simple cylinder volume equation. V = Bh, or Volume = Area of the Base multiplied by the height of the cylinder.
Since the base is a circle, we use "(pi)r^2" for our B. Thanks to PEMDAS, we square 3.50 before doing any multiplication within the parentheses.
Then we multiply the result of that by pi (or 3.14) and then further multiply the product of
that by 15, or our cylinder's height.
You now have the volume of a cylinder from a rectangle.